Formal evidence
The formal-evidence review accepted the recorded build, exact declarations, unfinished-step scan, and axiom evidence.
Analysis · formal theorem
The function-level Fourier transform agrees almost everywhere with its L² representative for ℝ → ℂ functions in both L¹ and L².
Scope: The narrow ℝ → ℂ, volume-measure L¹/L² Fourier compatibility bridge: the function-level Fourier transform agrees almost everywhere with the L² Fourier representative for functions in both L¹ and L².
Exact formal proposition
theorem fourier_ae_eq_l2_fourier_of_memLp_one_two
{f : ℝ → ℂ}
(hf_one : MeasureTheory.MemLp f 1 MeasureTheory.volume)
(hf_two : MeasureTheory.MemLp f 2 MeasureTheory.volume) :
FourierTransform.fourier f =ᵐ[MeasureTheory.volume]
((FourierTransform.fourier
(hf_two.toLp f : MeasureTheory.Lp ℂ 2 MeasureTheory.volume)) : ℝ → ℂ)The theorem at a glance

Accessible transcript
f ∈ L¹ ∩ L² ⇒ ℱfunction(f) =ᵐ ℱL²([f])
The checked proof embeds the L² representative as a tempered distribution, matches both transforms against smooth compactly supported tests, and uses local integrability to conclude almost-everywhere equality. It identifies representatives only up to a null set, not pointwise.
FOURIER ANALYSIS · REPRESENTATIVE COMPATIBILITY
ONE TRANSFORM, TWO CONSTRUCTIONS
FOR f : ℝ → ℂ WITH f ∈ L¹ ∩ L²
ℱfunction(f) =ᵐ ℱL²([f])
Equality holds almost everywhere.
f
FUNCTION-LEVEL ROUTE
L¹ makes the integral Fourier transform available.
ℱfunction(f)(ξ) = ∫ℝ f(x)e⁻²πixξ dx
e⁻²πixξ
L² ROUTE
L² supplies the unitary Fourier representative.
ℱL²([f]) ∈ L²(ℝ)
(unitary Fourier transform)
L²
Equal almost everywhere.
Differences can occur only on a set of measure zero.
THE BRIDGE
The two transforms give the same value against every smooth compactly supported test.
HOW THE PROOF MOVES
1 · EMBED THE L² TRANSFORM
View the L² representative as a tempered distribution.
2 · MATCH TEST INTEGRALS
φ
Schwartz duality identifies both actions.
3 · USE LOCAL INTEGRABILITY
Equal compactly supported tests force a.e. equality.
4 · IDENTIFY THE REPRESENTATIVES
ℱfunction(f) =ᵐ ℱL²([f])
EXACT SCOPE
Almost-everywhere equality for f ∈ L¹ ∩ L². Not pointwise equality, not a claim for arbitrary L² functions, and not a discrete Fourier transform.
Theorem schematic

f ∈ L¹ ∩ L² ⇒ ℱfunction(f) =ᵐ ℱL²([f])
When f belongs to both L¹ and L², its oscillatory-integral Fourier transform and its unitary L² Fourier representative determine the same measurable function almost everywhere. The theorem does not assert pointwise equality or cover arbitrary L² inputs.
Result boundary
The narrow ℝ → ℂ, volume-measure L¹/L² Fourier compatibility bridge: the function-level Fourier transform agrees almost everywhere with the L² Fourier representative for functions in both L¹ and L².
These AI-generated visuals explain the theorem and proof route; they are not proof evidence. Their publication review was completed separately from review of the formal result. The exact Lean proposition and checked source remain authoritative.
Line counts exclude blank lines; comments and documentation count. The total is the commit-pinned first-party Lean import closure; Mathlib and other third-party dependencies are excluded.
Continue the mathematics
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Review record
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